| # | Problem | Pass Rate (passed user / total user) |
|---|---|---|
| 11113 | Thousands Separator Lite |
|
| 10066 | I2P homework2a |
|
Description
To represent a decimal number clearly and formally, one must insert commas (,) for the thousands separators, and a period (.) to separate the integer part from the fractional part.
For example, the number "123456789.012" should be represented as "123,456,789.012".
Now you have 2 such numbers in the standard format, and you want to calculate the summation of them.
Input
There are 2 lines in each case, and each line contains a number T in the standard format, where 1,000,000 ≤ T ≤ 499,999,999 and NO fractional part.
Output
For each case, you should output one line that exactly contains the summation of the 2 numbers, which is a integer without any commas.
Sample Input Download
Sample Output Download
Tags
Discuss
Description
The input is a three-digit integer N that consists of digits 1-9 except 0. For example, 489 is such a number. The task is to reverse the order of the digits of N to get a new three-digit number M, and compute the average of the N and M. For example, if N is 489, then M is 984, and the answer should be 736.5.
Input
A three-digit integer consisting of 1-9 except 0
Output
The average of the input number and its reversal
The answer should be expressed as a floating point number with precision to the first decimal place. For example, 333.0 or 736.5
Note that you do not need to print ‘\n’ at the end of the output.