1149 - I2P(||) HT Chen Lab2 Scoreboard

Time

2017/03/07 13:10:00 2017/03/07 15:10:00

Clarification

# Problem Asker Description Reply Replier Reply Time For all team

# Problem Pass Rate (passed user / total user)
11283 rotate linked list
11336 Linked list - deletion & insertion

11283 - rotate linked list   

Description

Given a link list structure named Node.

 

typedef struct _Node {

    int data;

    struct _Node *next;

} Node;

 

Given a list, rotate the list to the left by k places, where k is non-negative and k is smaller than the count of nodes in linked list.

For example: 
Given 1->2->3->4->5->NULL and k = 3
return 4->5->1->2->3->NULL.

 

Input

The input contains 2 sequence of positive integers.The first sequence is to create a linked list of integers, except the last one, which is -1, indicating the end of the sequence. The second line is an integer k. 

Output

The output contains the sequence of resulting linklist.

Sample Input  Download

Sample Output  Download

Partial Judge Code

11283.c

Partial Judge Header

11283.h

Tags




Discuss




11336 - Linked list - deletion & insertion   

Description

This problem asks you:

  1. To create a linked list to store a sequence of positive integers.
  2. To delete some given integers in the linked list. If the node is not existing, do nothing.
  3. To insert an integer into an appropriate position in the linked list.

 

For example, if the input is

1 2 3 4 5 6 7 -1

1 1 4 -1

2

1 8

3 9

The first sequence is 1 2 3 4 5 6 7 -1, so a linked list is created as

The second sequence is 1 1 4 -1, so do the follows.

 

After p1=1, the list becomes

because the first node is 1.

 

After p2 = 1, the list becomes

because the first node is 2.

 

After p3 = 4, the list becomes

because the fourth node is 6.

 

The next number is 2, so you need to read two lines.

 

The first line is 1 8, so the data of new node is 8 and should be inserted at position 1. The list becomes

 

The second line is 3 9, so the data of new node is 9 and should be inserted at position 3. The list becomes

 

Finally, the answer is 8 3 9 4 5 7.

 

Note for those who are not familiar with partial judge:

 

You will be provided with main.c and function.h, and asked to implement function.c containing three function createList, deleteNode and insertNode.

For OJ submission:

       Step 1. Submit only your function.c into the submission block. (Please choose c compiler)

       Step 2. Check the results and debug your program if necessary.

 

Input

The input contains 3 parts:

1.  A sequence of positive integers as the linked list, except the last one, which is -1.

2. A sequence of positive integers as the position need to be deleted, except the last one, which is -1.

3. A number N means the number of inserted node, and next N lines contain a pair of number (X, Y). X is the position which you are asked to insert a new node into and Y is the data of the node.

Output

The output contains the sequence of resulting linklist.

Sample Input  Download

Sample Output  Download

Partial Judge Code

11336.c

Partial Judge Header

11336.h

Tags




Discuss