Description

Given a character pointer *ptr, and a character array *ary.  Use malloc function to allocate memory to *ary with size = (end - start), where end and start are two given variables.  For example, if start = 48 and end = 63, ary[0] is ‘0’, ary[1] is ‘1’, and the last element in the array is ary[14] is ‘>’.

Initially, pointer *ptr points to ary[0].  Next, a sequence of pairs (num,offset) will be given.  For each pair, use *ptr to output the character in the position &ary[num]+offset.  Continuing with the above example, if (num, offset) = (4, 4), then output = ‘8’.

main.c

#include <stdio.h> #include <stdlib.h> #include "function.h" int main() { char *ary; char *ptr; int start, end; scanf("%d %d", &start, &end); malloc_array(&ary, end - start); int i; for(i = start; i < end; i++){ ary[i - start] = i; } ptr = &ary[0]; int num,offset; do{ scanf("%d%d", &num, &offset); if(num != -1) print_ptr_offset(ptr, num, offset); }while(num != -1); free(ary); return 0; }

function.h

void malloc_array(char **ary, int array_size); void print_ptr_offset(char *ptr, int num, int offset);

Input

The first line is start and end

The other line is num and offset

If num is -1 then stop the program.

Output

Print each pointer of *ptr + num + offset

Note that you need to print a newline character ‘\n’ after each char.

Sample Input  Download

Sample Output  Download

Partial Judge Code

10910.c

Partial Judge Header

10910.h

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